state-vector
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| state-vector [May 11, 2026 at 14:58] – created yanevskiv | state-vector [May 14, 2026 at 11:38] (current) – external edit 127.0.0.1 | ||
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| + | # State vector | ||
| + | **State vector** is the vector representation of a quantum state. | ||
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| + | Quantum state is often written as a linear combination of basis states where the coefficients are probability amplitudes. For example, a qubit is often written in the following way using Dirac notation. | ||
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| + | $$\lvert\psi\rangle = a\lvert 0\rangle + b\lvert 1\rangle$$ | ||
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| + | But it's also a postulate of quantum mechanics that every quantum state lives in a Hilbert space. For qubits, that Hilbert space is $\mathbb{C}^2$. Hilbert space is by definition a complete inner product space. An inner product space is a vector space equipped with an inner product. Since $\mathbb{C}^2$ is a vector space, and $\lvert\psi\rangle$ is postulated to live in it, we can write the qubit as a column vector in $\mathbb{C}^2$: | ||
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| + | $$\lvert\psi\rangle = \begin{pmatrix}a\\b\end{pmatrix}\qquad a, | ||
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| + | Because Hilbert space satisfies vector space axioms we can also do a linear decomposition: | ||
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| + | $$\lvert\psi\rangle = a\begin{pmatrix}1\\0\end{pmatrix} + b\begin{pmatrix}0\\1\end{pmatrix}$$ | ||
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| + | From this, we see a natural definition of $\lvert 0\rangle$ and $\lvert 1\rangle$ | ||
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| + | $$\lvert 0\rangle = \begin{pmatrix}1\\ 0\end{pmatrix}$$ | ||
| + | $$\lvert 1\rangle = \begin{pmatrix}0\\ 1\end{pmatrix}$$ | ||
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| + | But this is just a convention. We could have chosen any other complex numbers to do define $\lvert 0\rangle$ and $\lvert 1\rangle$ and quantum mechanics would have worked the same way. Thus a state vector is just a linear algebra representation of a quantum state. | ||
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