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$\mathbb{CP}^1$
Complex projective line (or $\mathbb{CP}^1$) is the Hilbert space where pure qubits live in. It is defined as the quotient space of $\mathbb{C}^2$ and $\mathbb{C}$, both of which are punctured in their respective zero elements.
$$\mathbb{CP}^1 \stackrel{\text{def}}{=} (\mathbb{C}^2 \setminus\{0\})/\mathbb{C}^\times\qquad \mathbb{C}^\times\stackrel{\text{def}}{=}\mathbb{C} \setminus \{0\}$$
Motivation
To do quantum computing, we usually use the Hilbert space $\mathbb{C}^2$. That's the Hilbert space in which all qubit state vectors (or qubit “kets”) $\lvert\psi\rangle$ live in. However, many elements of this space correspond to something unphysical. For example, probabilities that don't add up to 100%. Also there are elements which we would consider to be duplicates of each other (up to a global phase).
Namely, we can identify 3 major issues.
- The zero vector is in $\mathbb{C}^2$ but it's unphysical. Applying the “Born rule” yields 0% + 0% = 0%. Meaning, the qubit doesn't even exist. This violates the second axiom of probability which states that probabilities must add up to 100%. $$\lvert\psi\rangle = \begin{pmatrix}0\\ 0 \end{pmatrix}\qquad \lvert\psi\rangle\in\mathbb{C}^2 \qquad |0|^2 + |0|^2 = 0$$ - There are many other states which violate the "Born rule" and are thus unphysical. For example, the following is a state which is in state $\lvert 0\rangle$ with 300% probability and in state $\lvert 1\rangle$ with 200% yielding total probability of 500%. But according to the second axiom of probabilitiy, the probabilities must add up to exactly 100%. $$\lvert\psi\rangle = \begin{pmatrix}\sqrt{3} \\ \sqrt{2}\end{pmatrix}\qquad \lvert\psi\rangle\in\mathbb{C}^2\qquad |\sqrt{3}|^2 + |\sqrt{2}|^2 = 3 + 2 = 5$$ - Global phase is something that comes out of $$\lvert\psi_1\rangle = \begin{pmatrix}1\\ 0\end{pmatrix}\qquad \lvert\psi_2\rangle = \begin{pmatrix}i \\ 0\end{pmatrix}$$. ## Construction fdsafdsa
